[R 통계분석] 독립표본 t 검정 | 이분산 가정
#1. 방법
t.test(x, y = NULL,
alternative = c("two.sided", "less", "greater"),
mu = 0, paired = FALSE, var.equal = FALSE,
conf.level = 0.95, ...)
▶ x,y 자리에 데이터 입력함.
▶ var.equal=FALSE 가 디폴트 값, 이분산 가정 t검정을 수행.
▶ 이분산가정 t검정을 Welch's t-test라고 부름.
#2. 예제
> 코드
set.seed(1)
height_male=rnorm(50,175,5)
height_female=rnorm(50,165,5)
#귀무가설 : height_male = height_female
t.test(height_male, height_female)
#귀무가설 : height_male < height_female
t.test(height_male, height_female, alternative="greater")
#귀무가설 : height_male > height_female
t.test(height_male, height_female, alternative="less")
> 실행결과
> t.test(height_male,height_female)
Welch Two Sample t-test
data: height_male and height_female
t = 10.984, df = 95.793, p-value < 2.2e-16
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
8.123654 11.707564
sample estimates:
mean of x mean of y
175.5022 165.5866
> t.test(height_male,height_female,alternative="greater")
Welch Two Sample t-test
data: height_male and height_female
t = 10.984, df = 95.793, p-value < 2.2e-16
alternative hypothesis: true difference in means is greater than 0
95 percent confidence interval:
8.41625 Inf
sample estimates:
mean of x mean of y
175.5022 165.5866
> t.test(height_male,height_female,alternative="less")
Welch Two Sample t-test
data: height_male and height_female
t = 10.984, df = 95.793, p-value = 1
alternative hypothesis: true difference in means is less than 0
95 percent confidence interval:
-Inf 11.41497
sample estimates:
mean of x mean of y
175.5022 165.5866
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